Form表单参数和Json参数传递区别

1 Form表单数据的传递

例如OkHttp

FormBody.Builder builder = new FormBody.Builder();
for (String s : params.keySet()) {

    Object v = params.get(s);
    builder.add(s, v != null ? v.toString() : "");
}


Request request = new Request.Builder().url(url)
        .addHeader("content-type", "application/json;charset:utf-8")
        .post(builder.build()).build();

Response response = client.newCall(request).execute();

if (response.isSuccessful()) {

    return response.body().string();
} else {

    return response.message();
}

2 Json格式数据的传递

 MediaType mediaType = MediaType.parse("application/json");
 //使用JSONObject封装参数
 JSONObject jsonObject = new JSONObject();
 try {
     for (String s : params.keySet()) {
         Object v = params.get(s);
         jsonObject.put(s, v != null ? v.toString() : "");
     }
 } catch (Exception e) {
 }
 //创建RequestBody对象，将参数按照指定的MediaType封装
 RequestBody requestBody = RequestBody.create(mediaType,jsonObject.toString())


 Request request = new Request.Builder()
         .url(url)
         .post(requestBody)
         .addHeader("sign", sign)
         .addHeader("signType", signType)
         .build();

 Response response = client.newCall(request).execute();

 if (response.isSuccessful()) {

     return response.body().string();
 } else {

     return response.message();
 }

如果将Form表单参数改成Json参数传递，因后台接收的方式会有所不同，接受不到前端传递的参数，因为其媒体类型（MediaType）不一样

springmvc 中requestbody 接收http请求的json数据，将json数据转换为java对象

@RequestMapping("/addOrUpdateRole")
public ApiResult changeAgent(@RequestBody @Valid StaffRoleParam param, BindingResult result) throws RpcInvokingException {
    log.info("staff ---- >> addOrUpdateRole execute, 参数: param = {}", JSON.toJSONString(param));
    

}

如果没有requestbody 默认就是form表单格式的请求